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  • Compound A contains 8.7% Hydrogen 74% Carbon and 17.3% Nitrogen. The molecular formula of the compound is, Given: Atomic masses of C,H and N are 12, 1 and 14 amu respectively. T

Compound A contains 8.7% Hydrogen 74% Carbon and 17.3% Nitrogen. The molecular formula of the compound is,

Given: Atomic masses of C,H and N are 12, 1 and 14 amu respectively.

The molar mass of the compound \mathrm{A} \text { is } 162 \mathrm{~g} \mathrm{~mol}^{-1} \text {. }

Option: 1

\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{~N}_{2}


Option: 2

\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{~N}


Option: 3

\mathrm{C}_{5} \mathrm{H}_{7} \mathrm{~N}


Option: 4

\mathrm{C}_{10} \mathrm{H}_{14} \mathrm{~N}_{2}


Answers (1)

best_answer

Given,

\\\mathrm{H\rightarrow 8.7\; \%}\\ \mathrm{C\rightarrow 74\; \%}\\ \mathrm{N\rightarrow 17.3\; \%}

Assume 100 g of compound

\mathrm{H \rightarrow 8.7 \mathrm{~g} \rightarrow \frac{8.7}{1}=8.7 \text { moles }}

\mathrm{C \rightarrow 74 \; g \rightarrow \frac{74}{12}=6.16 \text { moles }}

\mathrm{N \rightarrow 17.3\; g \frac{17.3}{14}=1.23 \text { moles }}

Thus, the simplest ratio 

\text{H=7 C=5 N=1}

Empirical formula will be \mathrm{C_{5}NH_{7}} having weight of \mathrm{81\; g\; mol^{-1}}

But given compound 'A' has mass of \mathrm{162\; g\; mol^{-1}}

So the formula will be \mathrm{C_{10}N_{2}H_{14}}

Hence, Option (4) is correct.

Posted by

seema garhwal

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