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  • Compound A reacts with and forms a compound B. Compound B reacts with <img alt="\ma

Compound A reacts with \mathrm{NH_{4}Cl} and forms a compound B. Compound B reacts with \mathrm{H_{2}O} and excess of \mathrm{CO_{2}} to form compound C which on passing through or reaction with saturated \mathrm{NaCl} solution forms sodium hydrogen carbonate.
Compound A, B and C, are respectively.

Option: 1

\mathrm{CaCl}_2, \mathrm{NH}_3, \mathrm{NH}_4 \mathrm{HCO}_3
 


Option: 2

\mathrm{Ca}(\mathrm{OH})_2, \mathrm{NH}_4^{\oplus},\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3
 


Option: 3

\mathrm{CaCl}_2, \mathrm{NH}_4^{\oplus},\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3
 


Option: 4

\mathrm{Ca}(\mathrm{OH})_2, \mathrm{NH}_3, \mathrm{NH}_4 \mathrm{HCO}_3


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HARSH KANKARIA

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