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  • Compound with molecular formula C3H6O can show :Option: 1 Positional isomerismOption: 2 Functional group isomerismOption: 3 Both positional isomerism and metamerism  Option: 4<

Compound with molecular formula C3H6O can show :
Option: 1 Positional isomerism
Option: 2 Functional group isomerism
Option: 3 Both positional isomerism and metamerism  
Option: 4 Metamerism

Answers (1)

best_answer

We know this formula for degree of unsaturation-????

\mathrm{\text { Degrees of Unsaturation }=\frac{2 C+2+N-H-X}{2}}

C3H6O has 3 C , 6 H , 0 N , 0 X.

So, 

\mathrm{\text { DOU}=\frac{2\times 3+2+0-6-0}{2}}=1 

It means A ring or a double bond is present.

All possible compounds are:

Metamerism is not possible with 3 carbons.

Positional isomerism is not present.

Functional group isomerism is present. functional groups: alcohol, ether, aldehyde, ketone, alkene, etc.

 Therefore, the Correct option is (2)

Posted by

Kuldeep Maurya

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