Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Compound with molecular formula C₃H₆O can show :
Option: 1 Positional isomerism
Option: 2 Functional group isomerism
Option: 3 Both positional isomerism and metamerism
Option: 4 Metamerism

Answers (1)

best_answer

We know this formula for degree of unsaturation-????

$\mathrm{\text { Degrees of Unsaturation }=\frac{2 C+2+N-H-X}{2}}$

C₃H₆O has 3 C , 6 H , 0 N , 0 X.

So,

$\mathrm{\text { DOU}=\frac{2\times 3+2+0-6-0}{2}}=1$

It means A ring or a double bond is present.

All possible compounds are:

Metamerism is not possible with 3 carbons.

Positional isomerism is not present.

Functional group isomerism is present. functional groups: alcohol, ether, aldehyde, ketone, alkene, etc.

Therefore, the Correct option is (2)

Posted by

Kuldeep Maurya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

5 g of Na₂SO₄ was dissolved in x g of H₂O. The change in freezing point was found to be 3.82⁰C. If Na₂SO₄ is 81.5% ionised, the value of x (K

A capacitor is made of two square plates each of side 'a' making a very small angle $\alpha$

A solution of m-chloroaniline, m-chlorophenol and m-chlorobenzoic acid in ethyl acetate was extracted initially with a saturated solution of NaHCO₃ to give fraction A. The leftover organic phase was extracted with d

Trending Articles/News

anam-khan

Engineering aspirant dies by suicide in Kota, fourth case this year

anam-khan

What is non-Aadhaar declaration in JEE Main 2025? Explain mismatch between image, face

anam-khan

Forgot JEE Main password 2025 for downloading admit card? Here’s what to do

Latest Question