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Concentrated \mathrm{HNO}_{3} reacts with Iodine to give
 

Option: 1

\mathrm{HI, \mathrm{NO}_{2}\: and \: \mathrm{H}_{2} \mathrm{O}}
 


Option: 2

\mathrm{HIO}_{2}, \mathrm{~N}_{2} \mathrm{O}$ and $\mathrm{H}_{2} \mathrm{O}


Option: 3

\mathrm{HIO}_{3}, \mathrm{NO}_{2}$ and $\mathrm{H}_{2} \mathrm{O}


Option: 4

\mathrm{HIO}_{4}, \mathrm{~N}_{2} \mathrm{O}$ and $\mathrm{H}_{2} \mathrm{O}


Answers (1)

best_answer

Reaction for concentrated \mathrm{HNO_{3}} with Iodine -

\mathrm{I_{2}+10\, HNO_{3}(conc.)\longrightarrow 2\, HIO_{3}+10\, NO_{2}+4\, H_{2}O}

Hence product obtained are \mathrm{HIO_{3},NO_{2}\, and\, H_{2}O}

Option (C) is correct.

Posted by

Deependra Verma

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