A horizontal rod of mass 10 gm and length 10 cm is placed on a smooth plane inclined at an angle of 60 degree with the horizontal, with the length of the rod parallel to the edge of the inclined plane. A uniform magnetic field of induction B is applied vertically downwards. If the current through the rod is 1.73 ampere, then the value of B for which the rod remains stationary on the inclined plane is
1.73 Tesla
1 / 1.73Tesla
1 Tesla
None of the above
As we learnt in
Total magnetic force -
- wherein
For equilibrium
mg sin = i l B cos
B = 1 T
Option 1)
1.73 Tesla
incorrect
Option 2)
1 / 1.73Tesla
incorrect
Option 3)
1 Tesla
correct
Option 4)
None of the above
incorrect