Get Answers to all your Questions

header-bg qa

 A machine gun fires 60.0 gram bullets at 6 bullets a second. If the velocity of the bullets is 600 m/s, then the average force on the machine gun is
 

  • Option 1)

    67.0 N

  • Option 2)

    75.0 N.

  • Option 3)

    94.0 N

  • Option 4)

    216 N.

 

Answers (1)

best_answer

As learnt in

Perfectly Elastic Collision -

Law of conservation of momentum and that of Kinetic Energy hold good.

- wherein

\frac{1}{2}m_{1}u_{1}^{2}+\frac{1}{2}m_{2}u_{2}^{2}= \frac{1}{2}m_{1}v_{1}^{2}+\frac{1}{2}m_{2}v_{2}^{2}

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

m_{1},m_{2}:masses

u_{1},v_{1}:initial \: and\: final \: velocity\: of \: the\: mass\ m_{1}

u_{2},v_{2}:initial \: and\: final \: velocity\: of \: the\: mass\ m_{2}

 

 We have, 0.06 kg / bullet x 6 bullet / second = 0.36 kg / sec

Average force = 0.36 kg/ sec x 600 m / sec = 216 kg ms-2

                                                                      = 216 N


Option 1)

67.0 N

This option is incorrect

Option 2)

75.0 N.

This option is incorrect

Option 3)

94.0 N

This option is incorrect

Option 4)

216 N.

This option is correct

Posted by

Plabita

View full answer