A machine gun fires 60.0 gram bullets at 6 bullets a second. If the velocity of the bullets is 600 m/s, then the average force on the machine gun is
 

  • Option 1)

    67.0 N

  • Option 2)

    75.0 N.

  • Option 3)

    94.0 N

  • Option 4)

    216 N.

 

Answers (1)

As learnt in

Perfectly Elastic Collision -

Law of conservation of momentum and that of Kinetic Energy hold good.

- wherein

\frac{1}{2}m_{1}u_{1}^{2}+\frac{1}{2}m_{2}u_{2}^{2}= \frac{1}{2}m_{1}v_{1}^{2}+\frac{1}{2}m_{2}v_{2}^{2}

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

m_{1},m_{2}:masses

u_{1},v_{1}:initial \: and\: final \: velocity\: of \: the\: mass\ m_{1}

u_{2},v_{2}:initial \: and\: final \: velocity\: of \: the\: mass\ m_{2}

 

 We have, 0.06 kg / bullet x 6 bullet / second = 0.36 kg / sec

Average force = 0.36 kg/ sec x 600 m / sec = 216 kg ms-2

                                                                      = 216 N


Option 1)

67.0 N

This option is incorrect

Option 2)

75.0 N.

This option is incorrect

Option 3)

94.0 N

This option is incorrect

Option 4)

216 N.

This option is correct

Most Viewed Questions

Preparation Products

Knockout BITSAT 2021

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout BITSAT-JEE Main 2021

An exhaustive E-learning program for the complete preparation of JEE Main and Bitsat.

₹ 27999/- ₹ 11999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions