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  • Confused! kindly explain, A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 s. Then the coefficient of friction is

A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 s. Then the coefficient of friction is

  • Option 1)

    0.02

  • Option 2)

    0.03

  • Option 3)

    0.06

  • Option 4)

    0.01

 

Answers (1)

As we learnt in

Kinetic or Dynamic Friction -

f_{K}\;\alpha\ R

f_{K}=\mu_{K} R

f_{K}= kinetic friction 

\mu_{K}= coefficient of kinetic friction

R = reaction

- wherein

f_{K}<F_{l}

\therefore\ \mu_{K}<\mu_{s}

\mu_{K}=depends on the nature of surface in contact.

 

 

 

: Frictional force provides the retarding force

\therefore\: \: \: \mu mg=ma

or     \mu=\frac{a}{g}= \frac{u/t}{g}= \frac{6/10}{10}= 0.06

Correct option is 3.


Option 1)

0.02

This is an incorrect option.

Option 2)

0.03

This is an incorrect option.

Option 3)

0.06

This is the correct option.

Option 4)

0.01

This is an incorrect option.

Posted by

Sabhrant Ambastha

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