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A vessel of volume 5 litre contains 1.4 g of nitrogen at a temperature 1800 K. The pressure of the gas if 30% of its molecules are dissociated into atoms at this temperature is :

  • Option 1)

    4.05 atm

  • Option 2)

    2.025 atm

  • Option 3)

    3.84 atm

  • Option 4)

    1.92 atm

 

Answers (1)

best_answer

As we learnt in

Ideal Gas Law -

PV=nRT

- wherein

P - Pressure

V - Volume

n - No. of Moles

R - Gas Constant

T - Temperature

 

 

         

                              N_{2}\: \: \: \: \: \: \rightarrow \: \: \: \: \: \: \: \: 2N

at \: \: t=0        \frac{1.4}{28}= \frac{1}{20}                0

at \: \: t=t_{f}        \frac{1}{20}\: \: \: -x                2x

 

but    x = 30% of   \frac{1}{20}= \frac{3}{200}

Final number of mole = \frac{1}{20}-x+2x= \frac{1}{20}+x= \frac{1}{20}+\frac{3}{200}= \frac{13}{200}

\therefore P=\frac{13}{200}\times \frac{0.0821\times 1800}{5}= 1.92\: atm.


Option 1)

4.05 atm

Incorrect

Option 2)

2.025 atm

Incorrect

Option 3)

3.84 atm

Incorrect

Option 4)

1.92 atm

Correct

Posted by

Aadil

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