The correct statement about ICl_{5} and ICl_{4}^{-} is:

  • Option 1)

    both is isostructural

  • Option 2)

    ICI_{5} is trigonal bipyramidal and ICI_{4}^{-} is tetrahedral

  • Option 3)

    ICI_{5} is square bipyramidal and ICI_{4}^{-} is tetrahedral

  • Option 4)

    ICI_{5} is square bipyramidal and ICI_{4}^{-} is square planar.

Answers (1)

ICI_{5} is square bipyramidal and ICI_{4}^{-} is square planar.

ICI_{5}  :- 

   

Square pyramidal 

l.P=1

b.P=5

hybridisation=sp^{3}d^{2}

 

ICI_{4}^{-}  :- 

Square planar

l.p=2  b.p=4

hybridisation=sp^{3}d^{2}

 


Option 1)

both is isostructural

Option 2)

ICI_{5} is trigonal bipyramidal and ICI_{4}^{-} is tetrahedral

Option 3)

ICI_{5} is square bipyramidal and ICI_{4}^{-} is tetrahedral

Option 4)

ICI_{5} is square bipyramidal and ICI_{4}^{-} is square planar.

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