Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Confused! kindly explain, - Chemical Thermodynamics - JEE Main-2

For a spontaneous reaction the \Delta G , equilibrium constant (K) and E^{\circ}_{cell}  will be respectively

  • Option 1)

      –ve, >1, +ve

  • Option 2)

    +ve, >1, –ve

  • Option 3)

    –ve, <1, –ve

  • Option 4)

    –ve, >1, –ve

 

Answers (1)

As we learnt in

Spontanous process -

\Delta G= \Delta H-\Delta T

 

- wherein

For spontanouse process \Delta G must be negative.

 

\Delta G= -nFE_{cell} 

or  ln K is +ve 

\Rightarrow k > 1 

Now \Delta G is -ve for a spontaneous reaction Ecell for such a reaction is +ve


Option 1)

  –ve, >1, +ve

Correct

Option 2)

+ve, >1, –ve

Incorrect

Option 3)

–ve, <1, –ve

Incorrect

Option 4)

–ve, >1, –ve

Incorrect

Posted by

Sabhrant Ambastha

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 session 2 result date announced; Steps to check NTA session 2 scores
anam-khan

JEE Main 2024 session 2 final answer key soon at jeemain.nta.ac.in; result on April 25
anam-khan

JEE Main 2024 Session 2: Last day to challenge answer key today

Latest Question