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  • Confused! kindly explain, - Chemical Thermodynamics - JEE Main-3

Directions: Question are based on the following paragraph.

Two moles of helium gas are taken over the cycle ABCDA, as shown in the P-T diagram.

Question: The work done on the gas in taking it from  D\; to\; A

  • Option 1)

    -414R\; \;

  • Option 2)

    \; \; +414R\;

  • Option 3)

    \; -690R\;

  • Option 4)

    \; +690R

 

Answers (1)

As we leant in

Work Done for Isothermal Reversible Compression of an ideal gas -

W= -nRT\ln \frac{V_{f}}{V_{i}}

V_{i}> V_{f}

 

- wherein

At constant temperature

P\, \alpha \frac{1}{V}

W= -nRT\, \ln \frac{P_{i}}{P_{f}}

P_{f}> P_{i}

 

 W_{DA}= 2.3 \ n R {T} \log \frac{P_{1}}{P_{2}}=-(2.302) (2) (R) (300) \log \left( \frac{1\times 10^{5}}{2\times 10^{5}}\right )

= + (2.3) (600R) (0.3) = 414R

 


Option 1)

-414R\; \;

Incorrect

Option 2)

\; \; +414R\;

Correct

Option 3)

\; -690R\;

Incorrect

Option 4)

\; +690R

Incorrect

Posted by

Vakul

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