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  • Confused! kindly explain, - Co-ordinate geometry - JEE Main-2

Let C be the circle with centre (0, 0) and radius 3 units. The equation of the locus of the mid points of chord of the circle C        that subtend an angle of  2\pi /3  at its centre is

  • Option 1)

    x^{2}+y^{2}=\frac{3}{2}

  • Option 2)

    x^{2}+y^{2}=1

  • Option 3)

    x^{2}+y^{2}=\frac{27}{4}

  • Option 4)

    x^{2}+y^{2}=\frac{9}{4}

 

Answers (1)

best_answer

As we learnt in 

Equation of a circle -

x^{2}+y^{2}=r^{2}

- wherein

Circle with centre \left ( O,O \right ) and radius r.

 In \Delta AOB

cos\frac{\pi}{3}=\frac{OB}{OA}

\sqrt{\frac{h^{2}+k^{2}}{3}}=\frac{1}{2}

h2 + k2 = 9/4


Option 1)

x^{2}+y^{2}=\frac{3}{2}

This is incorrect option

Option 2)

x^{2}+y^{2}=1

This is incorrect option

Option 3)

x^{2}+y^{2}=\frac{27}{4}

This is incorrect option

Option 4)

x^{2}+y^{2}=\frac{9}{4}

This is correct option

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Aadil

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