Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Confused! kindly explain, - Complex numbers and quadratic equations - JEE Main-5

The number of irrational roots of equation x^{2}+\left ( a+2 \right )x-\left ( 2a+8 \right )= 0 equals \left ( a\; \epsilon \; Q \right )

  • Option 1)

    0

  • Option 2)

    1

  • Option 3)

    2

  • Option 4)

    Can't be determined.

 

Answers (1)

best_answer

By observation, x=2 is a rational root, of the given equation & Since coefficients are real so other root will be also rational, hence number of irrational roots equals zero.

\therefore Option (A)

 

Nature of Rational roots -

If   P\left ( x \right )= 0  is a polynomial equation with rational coefficients then irrational roots always occur in conjugate pair.

- wherein

Sometimes one root is observed by observation and with this concept nature of other root can be decided.

 

 


Option 1)

0

This is correct

Option 2)

1

This is Incorrect

Option 3)

2

This is Incorrect

Option 4)

Can't be determined.

This is Incorrect

Posted by

prateek

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Advanced 2024: Chemical engineering cut-offs at IITs; know opening, closing ranks
anam-khan

IIT JEE Mains Result 2024 Session 2: How is overall merit list prepared?
anam-khan

JEE Mains Session 2 result 2024 soon; List of top NITs in India

Latest Question