current carrying loop is placed in a uniform magnetic field in four different orientations, I,II, III & IV arrange them in the decreasing order of potential Energy

I.

 

  • Option 1)

     I > III > II > IV
     

     

  • Option 2)

     I > II >III > IV
     

  • Option 3)

     I > IV > II > III
     

  • Option 4)

     III > IV > I > II

 

Answers (1)

As we learnt in 

Potential energy of current carrying coil -

U=-MB\cos \theta

U=-\underset{M}{\rightarrow}.\underset{B}{\rightarrow}

-

 

 Potential  energy U = -\vec{M}.\vec{B}

(I) angle between \vec{M} & \vec{B} is 180; U = MB

(II)angle between \vec{M} & \vec{B} is 90;U = 0

(III) angle between M & B is \theta (\theta < 90o), U = -MB cos \theta

(IV) angle between M & B is \theta(\theta>90o), U = + MB cos \theta

\therefore     I > IV > II > III


Option 1)

 I > III > II > IV
 

 

incorrect

Option 2)

 I > II >III > IV
 

incorrect

Option 3)

 I > IV > II > III
 

correct

Option 4)

 III > IV > I > II

incorrect

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