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  • Confused! kindly explain, Electric charge is uniformly distributed along a long straight wire of radius 1mm. The charge per cm length of the wire is Qcoulomb. Another cylindrical surface of radius 50 cm and length 1m symmetrically encloses the wire a

Electric charge is uniformly distributed along a long straight wire of radius 1mm. The charge per cm length of the wire is Qcoulomb. Another cylindrical surface of radius 50 cm and length 1m symmetrically encloses the wire as shown in the figure. The total electric flux passing through the cylindrical surface is

  • Option 1)

    Q/\varepsilon _0

  • Option 2)

    100Q/\varepsilon _0

  • Option 3)

    10Q/\pi \varepsilon _0

  • Option 4)

    100Q/\pi\varepsilon _0

 

Answers (1)

best_answer

As we have learned

if Electric field is variable -

\phi = \int \vec{E}\cdot d\vec{A}

-

 

 Charge enclosed by cylindrical surface (length 100 cm) is Q_{enc}= 100Q By applying Gauss's law \phi = 1(Q_{enc})/\varepsilon _0= 1(100Q)/\varepsilon _0

 

 


Option 1)

Q/\varepsilon _0

Option 2)

100Q/\varepsilon _0

Option 3)

10Q/\pi \varepsilon _0

Option 4)

100Q/\pi\varepsilon _0

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Aadil

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