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If there are n capacitors in parallel connected to V  volt source, then the energy stored is equal to

  • Option 1)

    CV

  • Option 2)

    \frac{1}{2}nCV^{2}

  • Option 3)

    CV^{2}

  • Option 4)

    \frac{1}{2n}CV^{2}

 

Answers (2)

best_answer

As we learnt in

Energy Stored -

U=\frac{1}{2}CV^{2}=\frac{1}{2}QV=\frac{Q^{2}}{2C}

-

 

 

Total \: capacity\: = nC

\therefore \: \: \: Energy= \frac{1}{2}nCV^{2}


Option 1)

CV

Incorrect

Option 2)

\frac{1}{2}nCV^{2}

Correct

Option 3)

CV^{2}

Incorrect

Option 4)

\frac{1}{2n}CV^{2}

Incorrect

Posted by

Plabita

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