Find the distance of the point from the charge of potential and field strength at that point is 600 V and 200 N/C.

  • Option 1)

    6 m

  • Option 2)

    7 m

  • Option 3)

    3.5 m

  • Option 4)

    3 m

 

Answers (1)

As we learnt in 

Electric field and potential Due to various charge Distribution i) Point Charge -

Electric field and Potential at Point P due to a Point charge Q.

E= \frac{kQ}{r^{2}}    ,     V= \frac{kQ}{r}

- wherein

 

 V = \frac{Kq}{r}\ \ and\ \ E=\frac{Kq}{r^{2}} = \frac{V}{r}

\Rightarrow r =\frac{V}{E} = 3\ m


Option 1)

6 m

Incorrect

Option 2)

7 m

Incorrect

Option 3)

3.5 m

Incorrect

Option 4)

3 m

Correct

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