For a normal curve the greatest ordinate is 

  • Option 1)

    2ps

  • Option 2)

    \sigma \sqrt{2\pi }

  • Option 3)

    \frac{1}{\sqrt{2\pi \sigma }}

  • Option 4)

    \frac{1}{\sigma \sqrt{2\pi }}

 

Answers (1)

as learnt in

Standard Deviation -

In case of discrete frequency distribution 

\sigma = \sqrt{\frac{\sum f_{i}x_{i}^{2}}{\sum f_{i}}-\left ( \frac{\sum f_{i}x_{i}}{\sum f_{i}} \right )^{2}}

-

 

 For a normal curve, the greatest ordinate is

= \frac{1}{\sigma \sqrt{2\pi }}


Option 1)

2ps

This option is incorrect

Option 2)

\sigma \sqrt{2\pi }

This option is incorrect

Option 3)

\frac{1}{\sqrt{2\pi \sigma }}

This option is incorrect

Option 4)

\frac{1}{\sigma \sqrt{2\pi }}

This option is correct

Preparation Products

Knockout BITSAT 2021

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout BITSAT-JEE Main 2021

An exhaustive E-learning program for the complete preparation of JEE Main and Bitsat.

₹ 27999/- ₹ 16999/-
Buy Now
Exams
Articles
Questions