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# Confused! kindly explain, Four capacitors of each of capacity 3μFare connected as shown in the adjoining figure. The ratio of equivalent capacitance between A and B and between A and C will be

Four capacitors of each of capacity 3μFare connected as shown in the adjoining figure. The ratio of equivalent capacitance between A and B and between A and C will be

• Option 1)

4:3

• Option 2)

3:4

• Option 3)

2:3

• Option 4)

3:2

438 Views

its wrong the option should be first one

As we learnt in

Series Grouping -

$\dpi{100} \frac{1}{C_{eq}}=\frac{1}{C_{1}}+\frac{1}{C_{2}}+\cdots$

- wherein

and

Parallel Grouping -

$\dpi{100} C_{eq}=C_{1}+C_{2}+\cdots$

- wherein

Between A and B, 3 capacitors are in series and they are in parallel with capacitance between A and B.

$C_{1} = \frac{C\times 3C}{C+3C} = \frac{3C}{4}$

Between A and C:

Two capacitors are in series and in turn they are parallel.

$C_{2} = \frac{2C\times 2C}{2C+2C} = C$

Ratio = $\frac{3}{4}$

Option 1)

4:3

Incorrect

Option 2)

3:4

Correct

Option 3)

2:3

Incorrect

Option 4)

3:2

Incorrect

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