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If <E> and <U> denote the average kinetic and the average potential energies respectively of mass describing a simple harmonic motion, over one period, then the correct relation is 

  • Option 1)

    <E> = <U>

  • Option 2)

    <E> = 2<U>

  • Option 3)

    <E> = -2<U>

  • Option 4)

    <E> = - <U>

 

Answers (1)

best_answer

In SHM for a complete cycle average value of Kinetic energy and potential energy are equal, i.e,

<E> = <U> = ^{1}/_{2}\cdot m\omega^{2}a^{2}

 

Potential energy in S.H.M. -

P.E.= \frac{1}{2}Kx^{2}

 

- wherein

Where K= m\omega ^{2}

 

 

 


Option 1)

<E> = <U>

This is correct.

Option 2)

<E> = 2<U>

This is incorrect.

Option 3)

<E> = -2<U>

This is incorrect.

Option 4)

<E> = - <U>

This is incorrect.

Posted by

prateek

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