Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Confused! kindly explain, One ticket is selected at random from 50 tickets numbered 00, 01, 02, ...., 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals

One ticket is selected at random from 50 tickets numbered 00, 01, 02, ...., 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals

  • Option 1)

    \frac{1}{7}

  • Option 2)

    \frac{5}{14}

  • Option 3)

    \frac{1}{50}

  • Option 4)

    \frac{1}{14}

 

Answers (1)

best_answer

As we learnt in 

Probability of occurrence of an event -

Let S be the sample space then the probability of occurrence of an event E is denoted by P(E) and it is defined as 

P\left ( E \right )=\frac{n\left ( E \right )}{n\left ( S \right )}

P\left ( E \right )\leq 1

P(E)=\lim_{n\rightarrow\infty}\left(\frac{r}{n} \right )

- wherein

Where n repeated experiment and E occurs r times.

 

If the product of the digit is zero, ticket must be one of 00, 01, 02, --- 09, 10, 20, 30, 40.

Total of 14 numbers, only one with sum= 8.

P(A)=\frac{1}{14}


Option 1)

\frac{1}{7}

This option is incorrect

Option 2)

\frac{5}{14}

This option is incorrect

Option 3)

\frac{1}{50}

This option is incorrect

Option 4)

\frac{1}{14}

This option is correct

Posted by

Plabita

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Maths 2025: Five tips to score high marks in ‘toughest’ subject; most important chapters
anam-khan

JEE Main 2025 exam city intimation slip for session 1 soon at jeemain.nta.nic.in
anam-khan

Focus on modern physics, formulas to solve tricky problems; 5 tips to tackle JEE Main physics 2025

Latest Question