Four persons can hit a target correctly with probabilities $\frac{1}{2},\frac{1}{3},\frac{1}{4}$ and $\frac{1}{8}$ respectively. If all hit at the target independently, then the probability that the target would be hit,is: Option 1) $\frac{25}{192}$ Option 2)  $\frac{7}{32}$ Option 3) $\frac{1}{192}$ Option 4) $\frac{25}{32}$

Answers (1)

$P$  (target is hit)

$=1-P$ (No one hit the target)

$=1-\left ( \frac{1}{2}\times \frac{2}{3}\times \frac{3}{4}\times \frac{7}{8} \right )$

$=\frac{25}{32}$

Option 1)

$\frac{25}{192}$

Option 2)

$\frac{7}{32}$

Option 3)

$\frac{1}{192}$

Option 4)

$\frac{25}{32}$

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