Four persons can hit a target correctly with probabilities \frac{1}{2},\frac{1}{3},\frac{1}{4} and \frac{1}{8} respectively. If all hit at the target independently, then the probability that the target would be hit,is:

  • Option 1)

    \frac{25}{192}

  • Option 2)

     \frac{7}{32}

  • Option 3)

    \frac{1}{192}

  • Option 4)

    \frac{25}{32}

 

Answers (1)

       P  (target is hit)

=1-P (No one hit the target)

=1-\left ( \frac{1}{2}\times \frac{2}{3}\times \frac{3}{4}\times \frac{7}{8} \right )

=\frac{25}{32}


Option 1)

\frac{25}{192}

Option 2)

 \frac{7}{32}

Option 3)

\frac{1}{192}

Option 4)

\frac{25}{32}

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