The correct order for acid strength of compounds 

CH\equiv CH,CH_{3}-C\equiv CH\: and\: CH_{2}=CH_{2}

is as follows :

 

 

  • Option 1)

    CH\equiv CH>CH_{2}= CH_{2}>CH_{3}-C\equiv CH

  • Option 2)

    CH_{3}-C\equiv CH>CH_{2}= CH_{2}>HC\equiv CH

  • Option 3)

    CH_{3}-C\equiv CH>CH\equiv CH >CH_{2}= CH_{2}

  • Option 4)

    HC\equiv CH>CH_{3}-C\equiv CH >CH_{2}= CH_{2}

Answers (1)
A admin

 

Application of Hyperconjugation -

More is the no of Hyperconjugation more is the stability of alkene

- wherein

 

   

sp carbon atoms are more electronegative than sp2 carbon atoms, which are in turn more electronegative than sp3 carbon atoms.

The reason for the difference in electronegativity is that p orbitals are on average further away from the nucleus than s orbitals, so the more p-orbital contribution you have to the hybrid orbital, the less electronegative the hybrid orbital. sp orbitals are said to have the greatest "s-character" and sp3 orbitals the least.


Option 1)

CH\equiv CH>CH_{2}= CH_{2}>CH_{3}-C\equiv CH

Option 2)

CH_{3}-C\equiv CH>CH_{2}= CH_{2}>HC\equiv CH

Option 3)

CH_{3}-C\equiv CH>CH\equiv CH >CH_{2}= CH_{2}

Option 4)

HC\equiv CH>CH_{3}-C\equiv CH >CH_{2}= CH_{2}

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