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# Confused! kindly explain, The mass and diameter of a planet are twice those of earth. The period of oscillations of pendulum on this planet will be ( if it is a second pedulum on earth )

The mass and diameter of a planet are twice those of earth. The period of oscillations of pendulum on this planet will be ( if it is a second pedulum on earth )

• Option 1)

$\frac{1}{\sqrt{2}}\: sec$

• Option 2)

$2\sqrt{2}\: sec$

• Option 3)

$2\: sec$

• Option 4)

$\frac{1}{2}\: sec$

Answers (1)
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$\\*g =\frac{G_{M}}{R^{2}} \Rightarrow g' = \frac{g}{2} \\* \frac{T'}{T} = \sqrt{\frac{g}{g'}} \left[T=2sec \right ] \\*\Rightarrow T' = 2\sqrt{2}$

Second's pendulum -

Simple pendulum whose time period is of 2 seconds

- wherein

* Length of simple pendulum is nearly 1 metre

Option 1)

$\frac{1}{\sqrt{2}}\: sec$

This is incorrect.

Option 2)

$2\sqrt{2}\: sec$

This is correct.

Option 3)

$2\: sec$

This is incorrect.

Option 4)

$\frac{1}{2}\: sec$

This is incorrect.

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