# Following figure shows two processes A and B for a gas. If $\Delta Q_{A}$ and $\Delta Q_{B}$ are the amount of heat absorbed by the system in two cases, and $\Delta U_{A}$ and $\Delta U_{B}$ are changes in internal energies, respectively, then : Option 1)  $\Delta Q_{A}< \Delta Q_{B},\Delta U_{A}< \Delta U_{B}$    Option 2) $\Delta Q_{A}> \Delta Q_{B},\Delta U_{A}> \Delta U_{B}$ Option 3) $\Delta Q_{A}> \Delta Q_{B},\Delta U_{A}= \Delta U_{B}$ Option 4)  $\Delta Q_{A}= \Delta Q_{B},\Delta U_{A}= \Delta U_{B}$

Internal energy is state function

So,     $u_{A}=u_{B}$

Now,    $\Delta Q=\Delta u- w$

Now    $w_{A}> w_{B}$  (work is Area under the curve

So,     $\Delta Q_{A}> Q_{B}$

Option 1)

$\Delta Q_{A}< \Delta Q_{B},\Delta U_{A}< \Delta U_{B}$

Option 2)

$\Delta Q_{A}> \Delta Q_{B},\Delta U_{A}> \Delta U_{B}$

Option 3)

$\Delta Q_{A}> \Delta Q_{B},\Delta U_{A}= \Delta U_{B}$

Option 4)

$\Delta Q_{A}= \Delta Q_{B},\Delta U_{A}= \Delta U_{B}$

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