Q

# Confused! kindly explain, Which of the following factors is of no significance for roasting sulphide ores to the oxides and not subjecting the sulphide ores to carbon reduction directly?

Which of the following factors is of no significance for roasting sulphide ores to the oxides and not subjecting the sulphide ores to carbon reduction directly?

• Option 1)

$CO_{2}$ is more volatile than  $CS_{2}$

• Option 2)

Metal sulphides are thermodynamically more stable than $CS_{2}$

• Option 3)

$CO_{2}$ is thermodynamically more stable than  $CS_{2}$

• Option 4)

Metal sulphides are less stable than the corresponding oxides

470 Views

As we learnt in

Roasting -

It is heating of the ore in presence of air below its fusion temperature.

- wherein

2PbS +3O3 $\rightarrow$ 2PbO + 2SO2

The reduction of metal sulphides by carbon reduction has positive  $\Delta G$ whereas, $\Delta G$ is negative for the same process with metal oxides. So, metal sulphides are more stable than oxides.

Option 1)

$CO_{2}$ is more volatile than  $CS_{2}$

This option is incorrect.

Option 2)

Metal sulphides are thermodynamically more stable than $CS_{2}$

This option is incorrect.

Option 3)

$CO_{2}$ is thermodynamically more stable than  $CS_{2}$

This option is incorrect.

Option 4)

Metal sulphides are less stable than the corresponding oxides

This option is correct.

Exams
Articles
Questions