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Consider an electron in the nth orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of the de Broglie wavelength \lambda of that electron as

Option: 1

(0.259) n \lambda


Option: 2

\sqrt{n} \lambda


Option: 3

(13.6) \lambda


Option: 4

n \lambda


Answers (1)

best_answer

\mathrm{\text{According to Bohr's theory }m v r=n \frac{h}{2 \pi}}
\mathrm{\Rightarrow Circumference\, 2 \pi r=n\left(\frac{h}{m v}\right)=n \lambda }
 

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