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Consider an elementary reaction \mathrm{3 A \rightarrow 2 B+C}. If the concentration of \mathrm{'A'} is tripled, how will the rate of the reaction change?

Option: 1

Rate will be doubled


Option: 2

Rate will be tripled


Option: 3

Rate will become 6 times.


Option: 4

Rate will increase by a factor of 27


Answers (1)

best_answer

Rate of a reaction is directly proportional to the concentration of \mathrm{A} raised to its order.

\mathrm{R=K(A)^{3} }

\mathrm{ \quad \text { If } A \rightarrow 3 A}

\mathrm{ R^{\prime}=K[3 A]^{3}=27 K[A] }
\mathrm{ R^{\prime}=27 R }

Posted by

Divya Prakash Singh

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