Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

Consider an elementary reaction \mathrm{3 A \rightarrow 2 B+C}. If the concentration of \mathrm{'A'} is tripled, how will the rate of the reaction change?

Option: 1

Rate will be doubled


Option: 2

Rate will be tripled


Option: 3

Rate will become 6 times.


Option: 4

Rate will increase by a factor of 27


Answers (1)

best_answer

Rate of a reaction is directly proportional to the concentration of \mathrm{A} raised to its order.

\mathrm{R=K(A)^{3} }

\mathrm{ \quad \text { If } A \rightarrow 3 A}

\mathrm{ R^{\prime}=K[3 A]^{3}=27 K[A] }
\mathrm{ R^{\prime}=27 R }

Posted by

Divya Prakash Singh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

75% criteria for JEE Main 2025 not removed; eligibility criteria for admission to IITs
anam-khan

BTech Admissions 2025 LIVE: AEEE phase 1 exam date out, JEE Mains registration ongoing; BITSAT, VITEEE updates
anam-khan

JEE Main 2025 Eligibility Criteria: What is state code of eligibility? Here’s list of qualifying exams

Latest Question