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Consider the carbanions given below:

The correct order of stability of the given carbanions is 

Option: 1

\mathrm{(I)>(II)>(III)> (IV)}


Option: 2

\mathrm{(IV)>(III)>(II)> (I)}


Option: 3

\mathrm{(II)>(I)>(III)> (IV)}


Option: 4

\mathrm{(II)>(III)>(IV)> (I)}


Answers (1)

best_answer

As we have learnt, 

Greater the number of alkyl groups connected to a carbanion, lesser is the stability.

The general order of stability of carbanions is given by

\mathrm{CH_3^-}> Primary > Secondary > Tertiary

Therefore, the correct answer is Option (1)

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chirag

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