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Consider the carbanions given below:

The hybridisation of carbon atoms carrying the negative charge in (I) and (II) respectively is

Option: 1

\mathrm{sp^3 , sp^3}


Option: 2

\mathrm{sp^3 , sp^2}


Option: 3

\mathrm{sp^2 , sp^3}


Option: 4

\mathrm{sp^2 , sp^2}


Answers (1)

best_answer

As we have learned,

Alkyl carbanions are \mathrm{sp^3 } hybridised while if the carbanion is involved in resonance, then the hybridisation of the carbon atom changes to  \mathrm{sp^2 }.

Hence, the hybridisations are respectively \mathrm{sp^3 } and  \mathrm{sp^2 }

Therefore, the correct answer is Option (2)

Posted by

shivangi.shekhar

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