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  • Consider the following reactions: <img alt="NaCl+K_{2}Cr_{2}O_{7}+H_{2}SO_{4} (conc.)\rightarrow A + side\ products" src="/latex-image/?NaCl&plus;K_%7B2%7DCr_%7B2%7DO_%7B7%7D&plus;H_%7B2%7DSO_%7B4%7D%20%28conc.%29%5Crightarrow%20A%20&plus;%

Consider the following reactions: NaCl+K_{2}Cr_{2}O_{7}+H_{2}SO_{4} (conc.)\rightarrow A + side\ products A+NaOH\rightarrow B + side\ products B+ H_{2}SO_{4} (dil.)+H_{2}O_{2}\rightarrow C+ side\ products The sum of the total number of atoms in one molecule each of A, B and C is:  
Option: 1 18
Option: 216
Option: 3 14
Option: 4 20
 

Answers (1)

best_answer

(A) = CrO2Cl2

(B) = Na2CrO4

(C) = CrO5 

Total atoms = 5 (A) + 7 (B) + 6 (C) = 18 atoms

Thus, the correct answer is 18.

Therefore, option(1) is correct

Posted by

Kuldeep Maurya

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