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Consider the reaction given below :

Br-CH_2-CH_2-Br+NaI\rightarrow CH_2= CH_2+NaBr+IBr

The given reaction is names as 

Option: 1

Dehalogenation of Vicinal dihalides

Option: 2

Dehydrohalogenation of alkyl halides

Option: 3

Hofmann reaction

Option: 4


Answers (1)


As we have learnt, 

Vicinal dihalides, on heating with Zn dust in methanol or ethanol produce alkene.

NaI in acetone can also be used in place of Zn dust.

This reaction is known as Dehalogenation of vicinal dihalides.

Br-CH_2-CH_2-Br+NaI\rightarrow CH_2= CH_2+NaBr+IBr

Therefore, option (1) is correct.

Posted by

Divya Prakash Singh

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