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  • Conversion of A follows parallel first order reaction giving B and C as: <img alt="" src="https://cdn.entrance360.com/media/uploads/2019/10/11/download-28.png" style="height:147px; width:150

Conversion of A follows parallel first order reaction giving B and C as:

The activation energy along the paths with rate constant k1 and k2 respectively are E1 and E2. What is the overall activation energy of the reaction?

Option: 1

\mathrm{\frac{k_1 E_1 + k_2 E_2 }{k_1 + k_2}}


Option: 2

\mathrm{\frac{2k_1 E_1 +3 k_2 E_2 }{2k_1 +3 k_2}}


Option: 3

\mathrm{\frac{k_1 E_1 + k_2 E_2 }{2k_1 + 3k_2}}


Option: 4

\mathrm{\frac{3k_1 E_1 +2 k_2 E_2 }{3k_1 +2 k_2}}


Answers (1)

best_answer

The overall activation energy is independant of the stoichiometric coefficient of the products.

Hence, the overall activation energy is given by

\mathrm{E_{a_{eff}}=\frac{k_1 E_1 +k_2 E_2 }{k_1 + k_2}}

Hence, the correct answer is Option (1)

Posted by

vishal kumar

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