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Copper has face centered cubic (fcc) lattice with interatomic spacing equal to\mathrm{2.54 \AA }. The value of lattice constant for this lattice is

Option: 1

2.54 \AA


Option: 2

\quad 3.59 \AA


Option: 3

\quad 1.27 \AA


Option: 4

\quad 5.08 \AA


Answers (1)

best_answer

Given interatomic spacing \mathrm{=2 \mathrm{r}=2.54 \mathrm{~\AA }}

\mathrm{4 \mathrm{r}=\sqrt{2} \mathrm{a},} where a is lattice constant\mathrm{2 \mathrm{r}=\frac{\sqrt{2} \mathrm{a}}{2}=\frac{\mathrm{a}}{\sqrt{2}}}

\mathrm{\mathrm{a}=2 \mathrm{r} \sqrt{2}=(2.54 \hat{\AA})(1.414)=3.59 \hat{\AA}}

 

 

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