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  • Current in the windings of the toroid is 2A. There are 400 turns & the mean circumferential length is 40cm. If the inside magnetic field is 1.0 T. The relative permeability is near to<div c

Current in the windings of the toroid is 2A. There are 400 turns & the mean circumferential length is 40cm. If the inside magnetic field is 1.0 T. The relative permeability is near to

Option: 1

400


Option: 2

200


Option: 3

300


Option: 4

100


Answers (1)

best_answer

As we learned

Toroid -

B=\frac{\mu _{oNi}}{2\pi r}=\mu _{o}ni

- wherein

n=\frac{N}{2\pi r}

 

 Where \mu r is also present

B=\frac{\mu o \mu rNI}{2\pi r}\rightarrow i\! f \mu r\; is \; al\! so\; present  

 

B=\frac{4\pi \times 10^{-7}\times 400\times \mu r\times 2}{0.4}\Rightarrow \mu r=400

Posted by

Ritika Jonwal

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