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  • Decomposition of an oxide by gold catalyst at at an initial pressure of 100 tor was 50 % in 46.06 sec

Decomposition of an oxide by gold catalyst at 980^{\circ} \mathrm{C} at an initial pressure of 100 tor was 50 % in 46.06 seconds and 99 % in 168.2 seconds. Then the velocity constant is?
 

Option: 1

1.5 \times 10^{-2} \mathrm{~s}^{-1}


Option: 2

1.2 \times 10^{-4} \mathrm{Ms}^{-1}


Option: 3

3.2 \times 10^{-3} \mathrm{M}^{-1} \mathrm{~s}^{-1}


Option: 4

None


Answers (1)

best_answer

Using first order kinetics,
\text{First case: }\mathrm{k=\frac{2.303}{46.06} \log \frac{100}{100-50}=\frac{0.3010}{20} s^{-1}=0.015 s^{-1} }\mathrm{\text{Second case: }k=\frac{2.303}{168.2} \log \frac{100}{100-92}=0.015 \mathrm{~s}^{-1} }As both k are same, so the order of the reaction is first order
and \mathrm{k=1.5 \times 10^{-2} \mathrm{~s}^{-1}}

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vinayak

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