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Decomposition of \mathrm{HCl[g]} on Platinum surface is zero order \mathrm{Rx}^n. Initial few mole of \mathrm{H}_2 are present in the reaction chamber then correct graph is?

Option: 1


Option: 2


Option: 3


Option: 4


Answers (1)

best_answer

\mathrm{2 \mathrm{HCl}(\mathrm{g}) \rightarrow \mathrm{H}_2(\mathrm{~g})+\mathrm{Cl}_2(\mathrm{~g})}

For zeroth order reaction 

\mathrm{x=k t}

but initially a moles were present, so. Product
\mathrm{P_{\mathrm{H}_2}=k t+a}

Thus correct ans. (b)

 

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seema garhwal

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