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Determine how many different ways 10 tiny ornaments can be arranged to form a chain.

Option: 1

362880

 


Option: 2

181440


Option: 3

362430

 


Option: 4

232430


Answers (1)

Let's put one tiny ornament in place. 

Now we must arrange the remaining 10 - 1 = 9 ornament. 

These 9 ornaments can be arranged in a variety of  ^{9}P_9   ways. Because there is no dependency on whether the tiny ornaments are arranged clockwise or anticlockwise. 

Hence, the number of ways required is given by,

\frac{9!}{2}=181440

Therefore, the required number of ways to form a chain is 181440.

Posted by

Sumit Saini

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