Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Determine the de Broglie wavelength of an electron that undergoes acceleration by a potential difference of 200 V. (Given:<img alt="h= 6.626\times 10^{-3}Js,m_{e}= 9.1 \times 10^{-31}kg, e= 1.6\tim

Determine the de Broglie wavelength of an electron that undergoes acceleration by a potential difference of 200 V. (Given:h= 6.626\times 10^{-3}Js,m_{e}= 9.1 \times 10^{-31}kg, e= 1.6\times 10^{-19}C )

Option: 1

1.23 \AA


Option: 2

0.616 \, \AA


Option: 3

2.46\, \AA


Option: 4

0.308\, \AA


Answers (1)

best_answer

Using the equation for the de Broglie wavelength of an electron, we have:

\lambda_{e}= \frac{h}{\sqrt{2m_{e}\left ( eV \right )}}

Substituting the given values, we get:
\lambda_{e}= \frac{6.626\times 10^{-34}}{\sqrt{2\times 9.1\times 10^{-31}\times 1.6\times 10^{-19}\times 200}}

Solving this expression, we get:

\lambda_{e} \approx0.308\, \AA

The resulting expression is then evaluated to obtain the de Broglie wavelength of the electron. The correct answer is an option (4).  

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 registration ends tomorrow; changes introduced in exam this year
anam-khan

BTech Admission 2025 Live: JEE Mains registrations closing tomorrow; VITEEE, MET exam dates out
anam-khan

JEE Main 2025 Live: NTA to close JEE registration on Friday; apply at jeemain.nta.nic.in, correction window

Latest Question