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  • Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is :Option: 1 1

Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is :

Option: 1

1.00 M


Option: 2

2.00 M


Option: 3

2.50 M


Option: 4

4.00 M


Answers (1)

best_answer

We have given, density of solution = 1.12g/ml

Therefore, total volume of solution = \frac{total weight\: of solutions}{density}

 

= \frac{\left ( 1000+120 \right )g}{1.12 g mL^{-1}} = 1 L

 

Now, total moles of solute  = \frac{120}{60} =2

Molarity is given as 
Molarity = (Moles of solute) / volume (L)
Thus, moles = 2 and volume = 1L

Therefore, molarity = 2 / 1

                            = 2M

Therefore, Option (2) is correct

Posted by

vinayak

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