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Distance of closest approach of \alpha particle :

Option: 1

decreases as the initial Kinetic Energy of the \alpha particle increases


Option: 2

increases as the initial Kinetic Energy of the \alpha particle increases


Option: 3

is independant of the initial Kinetic Energy of the \alpha particle


Option: 4

None of the above


Answers (1)

best_answer

As we have learnt,

The relation between distance and kinetic energy is given as follows:

\mathrm{KE}=\frac{1}{4 \mathrm{\pi e}_{0}} \times \frac{2 \mathrm{e} \times \mathrm{Ze}}{\mathrm{r}}

Thus, as the initial Kinetic energy of the \alpha particle decreases, the distance of closest approach increases

Therefore, Option(1) is correct 

Posted by

Divya Prakash Singh

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