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Due to a small magnet, the intensity at a distance n is the end on position is 9 gauss. What will be the intensity at a distance \frac{x}{2} on the broad side on position 

Option: 1

9 gauss 


 


Option: 2

4 gauss


Option: 3

36 gauss


Option: 4

4.5 gauss


Answers (1)

best_answer

 

 

 InC.G.S Baxial =9 =\frac{2M}{x^{3}}\cdots \cdots (i)

B equatrorial = \frac{M}{\left ( \frac{x}{3} \right )^{3}}=\frac{8M}{x^{3}}\cdots \cdots (ii)

from equation (i) and (ii), B equitorial = 36 gauss

 

 

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shivangi.shekhar

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