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  • Eight copper wire of length  and diameter are joined in parallel to f

Eight copper wire of length \mathrm{l} and diameter \mathrm{d} are joined in parallel to form a single composite conductor of resistance \mathrm{R}. If a single copper wire of length \mathrm{2 l}  have the same resistance \mathrm{(R)} then its diameter will be_____________\mathrm{d}.

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

 Case I: Eight copper wire in parallel,

\mathrm{\frac{1}{R}=\frac{1}{R_{e q}}=\frac{8}{R_0}=\frac{8\left(\pi d^2 / 4\right)}{s l} }

\mathrm{ \quad R=\frac{s l}{2 \pi d^2} \rightarrow(1)}

Case II.

\mathrm{R=\frac{\rho(2 l)}{\pi\left(d^{\prime}\right)^2}=\frac{s l}{2 \pi d^2} }

\mathrm{d^{\prime}=2 d}

\therefore The diameter will be \mathrm{2 d}

Posted by

Suraj Bhandari

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