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Electrons are accelerated by a potential difference of 54 V in the Davisson-Germer experiment. What is the de Broglie wavelength of these electrons?

Option: 1

0.082 nm


Option: 2

0.125 nm
 


Option: 3

0.167 nm

 


Option: 4

0.204 nm


Answers (1)

best_answer

According to de Broglie, \lambda_e=\frac{12.27}{\sqrt{V}} A^{\circ}

and using V = 54 Volt we get \lambda_e=0.167 \mathrm{~nm}

Posted by

Shailly goel

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