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Equal weighs of ethane and hydrogen are mixed in an empty container at 25^{\circ} \mathrm{C}. The fraction of the total pressure exerted by Hydrogen is -

Option: 1

1:2


Option: 2

1:1


Option: 3

1:16


Option: 4

15:16


Answers (1)

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let X g of each gas is mixed.
           \mathrm{ \text { mole of ethane }=\frac{x}{30} }
           \mathrm{ \text { mole of hydrogen }=\frac{x}{2}}

\mathrm{\therefore}   Mole fraction of hydrogen \mathrm{=\frac{x / 2}{x / 2+x / 30}=\frac{15}{16}} 

\mathrm{\Rightarrow \frac{\text { partial pressure of } \mathrm{H}_2}{\text { Total pressure }}=\text { mole fraction of Hydrogen }}

\mathrm{=15:16}

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vishal kumar

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