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  • Figure shows a part of an electric circuit. The potentials at points a, b and c are 30 V, 12 V and 2 V respectively. The current through the 20 <img alt="\Omega" src="https://entranceco

Figure shows a part of an electric circuit. The potentials at points a, b and c are 30 V, 12 V and 2 V respectively.
The current through the 20 \Omega  resistor will be

               

Option: 1

1.0 A


Option: 2

0.2 A


Option: 3

0.4 A


Option: 4

0.6 A


Answers (1)

best_answer

Let potential of the junction be x volts
using junction law ii + i2 + i3 = 0

or  \frac{x-30}{10}+\frac{x-12}{20}+\frac{x-2}{30}=0

\begin{aligned} & \text { or } \frac{1}{60}[6 x-180+3 x-36+2 x-4]=0 \\ & \text { or } \frac{1}{60}[11 x-220]=0 \\ & \text { or } x=\frac{220}{11}=20 \mathrm{~V} \end{aligned}

current through 20 \Omega  is   =\frac{x-12}{20}

i_{2}=\frac{20-12}{20}=0.4A

 

Posted by

Gautam harsolia

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