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Figure shows a square loop ABCD with edge length a. The resistance of the wire ABC is r and that of ADC is 2r. The value of magnetic field at the centre of the loop assuming uniform wire is 

Option: 1

\mathrm{\frac{\sqrt{2} \mu_0 i}{3 \pi a} \odot }


Option: 2

\mathrm{\frac{\sqrt{2} \mu_0 i}{3 \pi a} \otimes }


Option: 3

\mathrm{\frac{\sqrt{2} \mu_0 i}{\pi a} \odot }


Option: 4

\mathrm{\frac{\sqrt{2} \mu_0 i}{\pi a} \otimes }


Answers (1)

best_answer


\mathrm{2 \times \frac{i}{3} \times \frac{\mu_0 \mathrm{l}}{4 \pi \frac{\mathrm{a}}{2}} \times\left[\cos 45^{\circ}+\cos 45^{\circ}\right]}

Dominated by ABC

Posted by

SANGALDEEP SINGH

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