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  • FInd out total magnetic field intensities at given point O : I current is flowing in the loop  <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAScAAADlCAIAAACeb6YdAAAgAElEQVR

FInd out total magnetic field intensities at given point O : I current is flowing in the loop 

Option: 1

\frac{\mu_0 I}{2\pi }


Option: 2

\frac{\mu _0}{4 \pi a}[\sin \alpha +\sin \beta ]


Option: 3

0


Option: 4

none 


Answers (1)

best_answer

Magnetic field due to current carrying arc

B= \frac{\mu_0 I \theta}{4 \pi r}

The magnetic field due to the upper and lower semi-circular arc is same in magnitude \left (B= \frac{\mu_0 I \pi}{4 \pi r} \right )  but opposite in direction, the net field at the centre is zero

Posted by

Nehul

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