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Find the equation of line parallel to y-axis and drawn through the point of intersection of the lines x-7 y+5=0 and  3 x+y=0

 

Option: 1

\begin{aligned} & 22 x+5=0 \\ \end{aligned}


Option: 2

10 x-4=0 \\


Option: 3

23 x+5=1 \\


Option: 4

47 x+9=10


Answers (1)

best_answer

On solving the equations x-7 y+5=0and   3 x+y=0 by using point of 

intersection formula, we get

x=\frac{-5}{22} \: and\: y=\frac{15}{22}

So, given lines intersect at \left(\frac{-5}{22}, \frac{15}{22}\right)

Let the equation of the required line be

x=\lambda......(i)

because the equation of a line parallel to y-axis is x = constant.

Since, equation (i) passes through \left(\frac{-5}{22}, \frac{15}{22}\right)

\lambda=\frac{-5}{22}

Substituting the value of \lambda in equation (i), we get

x=\frac{-5}{22}\: or \: 22 x+5=0

as the equation of the required line.

 

 

Posted by

Rishi

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