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Find the number of ways in which 10 different balls can be arranged on a shelf so that 4 particular balls shall not be together.

Option: 1

1314030


Option: 2

4315640 


Option: 3

2508730 

 


Option: 4

3507840 


Answers (1)

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Given that,

There are 10 different balls that can be arranged on a shelf so that 4 particular balls shall not be together.

The number of ways in which 10 balls can be arranged is 10!

The number of ways, when 4 particular balls are together, is given by,

7!\times4!

So, the number of ways when 4 particular balls are not together is given by,

10!-7!\times4!

Thus,

10!-7!\times4! =3628800-5040\times24

10!-7!\times4! =3507840

Therefore, the total number of ways for placing the balls is 3507840 ways.

 

Posted by

Ritika Jonwal

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